Let A=a11a21a31a12a22a22a13a23a33 be Positive-Definite Matrix.
Then, A=LL⊺=L11L21L310L22L3200L33L1100L21L220L31L32L33=L112L21L11L31L11L212+L222L31L21+L32L22(symmetric)L312+L322+L332
By setting the first-row first-column entry L11=a11, can find other entries using substitution.
L21=a21/L11,L31=a31/L11,L22=a22−L212,L32=(a32=L31L21)/L22,L33=a33−L312−L322
By summarizing, Lii=aii−∑k=1i−1Lik2, Lij=Ljj1(aij−∑k=1j−1LikLjk)