If A is a Pi-System containing the universal set Ω on the finite Measure Space(Ω,σ(A),μ), then the Finite Measureμ:σ(A)→[0,μ(Ω)<∞] is uniquely determined by the finite measure-like function on the Pi-Systemμ∗:A→[0,μ(Ω)<∞]
If A is a Semiring on Ω, and the function (pre-measure) m~:A→[0,∞] satisfies the following conditions, then the function m~ uniquely extended to the Measure on (Ω,σ(A)).
Conditions
m~(∅)=0
additivity: m~(i=1⨄nBi)=∑i=1nm~(Bi)
σ-sub additivity: m~(i=1⋃∞Ai)≤∑i=1∞m~(Ai)
σ-finite: ∃{Ai}i=1∞⊂A,s.t.m(Ai)<∞,i=1⋃∞Ai=Ω
The conditions 1~3: m~ satisfies measure-like conditions on A
The condition 4: m~ satisfies Sigma-Finite Measure-like condition on A, it makes the extension result unique.
Let (X,T) be a Topological Space, where X is the set and T is the topology on X.
The Borel sigma-field B(X) is the smallest Sigma-Field that contains all open sets in T.
R:=B(R)=σ(A1)=σ(A2)=⋯=σ(A9)
The above sets are all the Borel sigma-field.
Proof
Every element of σ(A) is generated by the elements of A and the complementary set and countable union by the conditions of Sigma-Field
If σ(A1) can be generated by A1 and the operations, and A1 can be generated by A2 and the operations, then A2 also generate σ(A1)
Therefore, σ(A1)=σ(A2)
An element of Borel sigma-field B∈B(X) is called Borel set.
A measurable function is a function f:Ω→S whose inverse function X−1(B) is F-measurable the two measurable spaces(Ω,F),(S,S).
Other Expressions
f:Ω→S is a measurable function on the two measurable spaces(Ω,F),(S,S)f:(Ω,F)→(S,S)f is F−S measurable
f∈F (only if (S,S)=(R,R))
f is a S-valued measurable
Examples
When (S,S)=(R,R), the measurable function is called a Random Variable.
When (S,S)=(Rd,Rd), the measurable function is called a Random Vector.
Facts
For the F-measurable set A∈F on the two measurable spaces(Ω,F),(R,R)
A function f:Ω→R defined as f(ω)={10ω∈Aω∈A is a F−R measurable function
If f is a R-valued measurable function on the two measurable spaces(Ω,F),(R,R), then ∀α∈R,αf(ω) also R-valued measurable.
Scaling of function does not change the Domain, only scale the Image
If f:(Ω,F)→(S,S) and g:(S,S)→(T,T) on the three measurable spaces(Ω,F),(S,S),(T,T), then g∘f:(Ω,F)→(T,T)
If a function f:R→R is continuous, is measurable.
If two functions f,g are R-valued measurable on the two measurable spaces(Ω,F),(R,R), then following are all R-valued measurable
h:=f+g
h:=f−g
h:=max(f,g), where h:ω↦max(f(ω),g(ω))
h:=min(f,g), where h:ω↦min(f(ω),g(ω))
If every element of a function sequence {fn:n∈N} is R-valued measurable, then the following are all R-valued measurable.
Approximation of Lebesgue Integral with Finite Sum
∫fdλ≈i=1∑Nanλ(An)
where An:={x∣f(x)=an} or An=f−1({an}).
To compute the Riemann Integral of f, one partitions the domain [a,b] into sub-intervals, while in the Lebesgue integral, one partitions the image of f.
Consider a measure spaces(Ω,F,μ) and a Measure Space(R,R), and a positive F−RmeasurableSimple Function, f:(Ω,F)→(R,R), with CodomainR:={r1,r2,…,rn} that have corresponding preimages f−1(ri)=Ai∈F.
Then the Lebesgue integral of the function f with respect to μ is defined as
∫Ωfdμ=∑i=1nriμ(Ai)
Facts
Consider a measure spaces(Ω,F,μ) and a Measure Space(R,R), and a positive F−RmeasurableSimple Function, f:(Ω,F)→(R,R), with CodomainR:={r1,r2,…,rn} that have corresponding preimages f−1(ri)=Ai∈F. Then,
f=∑i=1mαi1Ai=∑j=1nβj1Bj⟹∫fdμ=∑i=1nαiμ(Ai)=∑i=1nβiμ(Bi)
Consider a measure spaces(Ω,F,μ) and a Measure Space(R,R) and a positive Measurable Functionf:(Ω,F)→(R,R).
Then the Lebesgue integral of the function f with respect to μ is defined as
∫Ωfdμ:=sup{∫Ωφdμ0≤φ≤f,a.e. w.r.t.μ}
where each φ:(Ω,F)→(R,R) is a Simple Function.
Consider a measure spaces(Ω,F,μ) and a Measure Space(R,R) and a Measurable Functionf:(Ω,F)→(R,R).
Then the Lebesgue integral of the function f with respect to μ is defined as
∫Ωfdμ:=∫Ωf+dμ−∫Ωf−dμ
where f+:=max(0,f) and f−:=max(0,−f) for the function f.
Existence of Integral
∫fdμ exists
∫f+dμ<∞ and ∫f−dμ<∞ (f is integrable w.r.t μ)
∫fdμ=∫f+dμ−∫f−dμ
μ≪λ
Consider measuresμ,λ on a Measurable Space(Ω,F).
The measure μ said to be absolutely continuous with respect to λ, or μ is dominated by λ, denoted by μ≪λ, If
∀S∈F,λ(S)=0⇒μ(S)=0
Given a measure space (S,S,λ) and a non-negative Measurable Functionf:S→R0+, we can define a new measure μ by the relation
∀B∈S,μ(B)=∫Bfdλ
The measure μ is absolutely continuous with respect to λ (μ≪λ) and f be a Radon-Nikodym derivative of μ with respect to λ.
The expected value of the Random VariableX when FX satisfies absolute continuous over #, μX<<#X
In other words, FX has at most countable jumps.
Expected Value of a Function
E(g(x))=∫Rg(x)dμX
Continuous
E(g(x))=∫Rg(x)fX(x)dx
Discrete
E(g(x))=x∈SX∑g(x)pX(x)
Properties
Linearity
Random Variables
If ∃kiE[Xi], then
E[∑i=1nkiXi]=∑i=1nkiE(Xi)
Matrix of Random Variables
Let W1,W2 be a m×n matrices of random variables, A1,A2 be k×m matrices of constants, and B a n×l matrix of constant. Then,
E[A1W1+A2W2]=A1E[W1]+A2E[W2]
E[A1W1B]=A1E[W1]B
Notations
Expression
Discrete
Continuous
Expression for the event 2Ω and the probability P
∑ω∈ΩX(ω)⋅P(ω)
∫ΩX(ω)⋅dP(ω)
Expression for the measurable space (R,R) and the distribution μX